In this article, I will introduce Lie algebra, which essentially is related to the Poisson brackets we studied before.

Definition

Lie Algebra

For a vector space V defined on field F , a Lie algebra is tuple V,[,] , where [,] is a bilinear mapping: [,]:V×VV , s.t. all of the 3 following conditions are fulfilled:

  1. Bilinearity:
[ax+by,z]=a[x,z]+b[y,z],x,y,zV.
  1. Anti-Symmetry:
[x,x]=0,xV.

If the field F does not have character 2 , we also have

[x,y]=[y,x],x,yV.
  1. Jacobi Identity:
[x,[y,z]]+[y,[z,x]]+[z,[x,y]]=0,x,y,zV.

Comment 1.: The character of a field F is defined as:

char(F)=argminn>0(1+1+...+1n times=0),

if n= , char(F):=0 .

Comment 2.: If we denote adx(y)=[x,y] (derivation), Jacobi identity can be rewritten as:

adx([y,z])=[y,adx(z)]+[adx(y),z].

Why Poisson brackets have Lie algebra structure

What is Poisson bracket

See the link.

Poisson Bracket
{Q1,Q2}=Q1xQ2pQ1pQ2x,

where Q1,Q2 are observables.

Easy to know that, Poisson brackets are bilinear and anti-symmetric. For the Jacobi identity, the proof is technical but not too difficult. This is an exercise for the reader.

Jacobi identity is an interesting property, because we know in Hamiltonian mechanics the time evolution of observables can be written:

f˙={f,H}.

If f,g are conserved ( {f,H}={g,H}=0 ), from Jacobi identity:

{f,{g,H}}+{g,{f,H}}+{H,{f,g}}=0{{f,g},H}=0.

{f,g} is also conserved! This implies that the conserved quantities form a Lie subalgebra.

Moreover, if we define the derivation operator Xf(g)={f,g} , from Jacobi identity we can write:

X{f,g}=XfXgXgXf.

Poisson algebra

Poisson’s bracket is as a matter of fact stronger than the bilinear mapping required by Lie algebra in the way that it satisfies the Leibniz rule in addition:

{f,gh}={f,g}h+g{f,h},

or in the derivation notation

Xf(gh)=Xf(g)h+gXf(h).

This rule, which is a generalization of the product rule of derivative, makes V,{,} a Poisson algebra.